Assume integer is 2 bytes wide. How many bytes will be allocated for the following code?
#include<stdio.h>
#include<stdlib.h>
#define MAXROW 3
#define MAXCOL 4
int main()
{
int (*p)[MAXCOL];
p = (int (*) [MAXCOL])malloc(MAXROW *sizeof(*p));
return 0;
}
What will be the output of the program?
#include<stdio.h>
#include<stdlib.h>
int main()
{
union test
{
int i;
float f;
char c;
};
union test *t;
t = (union test *)malloc(sizeof(union test));
t->f = 10.10f;
printf("%f", t->f);
return 0;
}
What will be the output of the program?
#include<stdio.h>
#include<stdlib.h>
int main()
{
char *s;
char *fun();
s = fun();
printf("%s\n", s);
return 0;
}
char *fun()
{
char buffer[30];
strcpy(buffer, "RAM");
return (buffer);
}
What will be the output of the program (16-bit platform)?
#include<stdio.h>
#include<stdlib.h>
int main()
{
int *p;
p = (int *)malloc(20);
printf("%d\n", sizeof(p));
free(p);
return 0;
}
What will be the output of the program?
#include<stdio.h>
#include<stdlib.h>
int main()
{
int *p;
p = (int *)malloc(20); /* Assume p has address of 1314 */
free(p);
printf("%u", p);
return 0;
}